Back to GCSE Physics Revision Home

Energy Calculations

GCSEAQACombined Science FoundationCombined Science HigherPhysics FoundationPhysics Higher

Energy Calculations Revision

Energy Calculations

The amount of energy stored kinetic, gravitational and elastic potential energy stores can be calculated using different equations. Energy is measured on Joules (J)

Kinetic Energy

Whenever an object is moving, it has energy in its kinetic energy store. The amount of kinetic energy depends on the mass and velocity of the object.

You can calculate the amount of energy in an object’s kinetic energy store (\bold{E_k}) using the following formula:

E_k = \dfrac{1}{2} m v^2

  • m= the mass of the object in kilograms \text{(kg)}
  • v= the velocity of the object in metres per second \text{(m/s)}.
GCSECombined Science FoundationCombined Science HigherPhysics FoundationPhysics HigherAQA

Gravitational Potential Energy

When an object is lifted in a gravitational field, it gains energy in its gravitational potential energy store. The amount of gravitational potential energy depends on the mass of the object, how high it has been lifted and the strength of the gravitational field. On Earth, the gravitational field strength is approximately 9.8\text{ m/s}^2.

The amount of energy in the gravitational potential energy store (\bold{E_p}) can be calculated using the following formula: 

E_p = mgh

  • m= the mass of the object in kilograms \text{(kg)}
  • g= the gravitational field strength in newtons per kilogram \text{(N/kg)}
  • h= the change in the height of the object in metres \text{(m)}.

You may have to calculate the height the object has been lifted by subtracting the starting height from the final height

GCSECombined Science FoundationCombined Science HigherPhysics FoundationPhysics HigherAQA

Elastic Potential Energy

When an object is stretched or squashed, it gains energy in its elastic potential store. The amount of elastic potential energy depends on the extension (distance the object is stretched or squashed) and the spring constant of an object. The spring constant is individual to each object and is measured in Newtons per metre (\text{N/m}). 

The amount of elastic potential energy (\bold{E_e}) stored in an object can be calculated using the following formula: 

E_e = \dfrac{1}{2} k x^2

  • k= the spring constant of the object measured in newtons per metre \text{(N/m)}
  • x = the extension (or compression) of the object in metres \text{(m)}. This is shown on the diagram on the right.

You may have to calculate the extension of the object by subtracting the final length from the starting length

GCSECombined Science FoundationCombined Science HigherPhysics FoundationPhysics HigherAQA
MME Logo
TikTok

Your 2024 Revision Partner

@mmerevise

Open TikTok

Example: Calculating Elastic Potential Energy

A 10\text{ cm} long wire with a spring constant of  5\text{ N/m} is stretched until it measures 12\text{ cm}. Calculate the potential energy stored by the stretched wire. 

Step 1: Calculate the extension of the wire:

\begin{aligned} x &= \color{f21cc2}{12\text{ cm}}- \color{f43364}{10\text{ cm}}\\&= 2\text{ cm}\\&=  \color{00bfa8}{0.02\text{ m}} \end{aligned}

Step 2: Calculate the elastic potential energy stored by the wire:

\begin{aligned}E_e  &= \dfrac{1}{2}kx^2 \\  &=\dfrac{1}{2}\times \color{f95d27}{5\text{ N/m}} \times \color{00bfa8}{(0.02\text{ m})}^2 \\ &= \color{black}{\bold{0.001 \text{ J}}} \end{aligned}

 

GCSECombined Science FoundationCombined Science HigherPhysics FoundationPhysics HigherAQA

Energy Calculations Example Questions

Push the ball so that it rolls along the floor. This increases the kinetic energy.

or

Lift the ball above the ground. This increases the gravitational potential energy

or 

Squash the ball. This increases the elastic potential energy

Accept suitable alternatives. 

MME Premium Laptop

Save your answers with

MME Premium

Gold Standard Education

\bold{E_k = \dfrac{1}{2}mv^2}

 

E_k= \dfrac{1}{2}\times3\times2^2 = \bold{6\text{ J}}
MME Premium Laptop

Save your answers with

MME Premium

Gold Standard Education

  \bold{E_p = mgh} = 85\times9.8\times3 = \bold{2 500}\text{ J (2 sf)}
MME Premium Laptop

Save your answers with

MME Premium

Gold Standard Education

  \text{extension} =5\text{ cm}-4\text{ cm}=\bold{1\text{ cm}} \\   \bold{E_e = \dfrac{1}{2}kx^2} \\ = \dfrac{1}{2}\times10\times1^2 = \bold{5\text{ J}}
MME Premium Laptop

Save your answers with

MME Premium

Gold Standard Education

MME Premium
Product

MME Premium Membership

£19.99

/month

Learn an entire GCSE course for maths, English and science on the most comprehensive online learning platform. With revision explainer videos & notes, practice questions, topic tests and full mock exams for each topic on every course, it’s easy to Learn and Revise with the MME Learning Portal.

Sign Up Now